0=3x^2-88x+484

Solution for 0=3x^2-88x+484 equation:

0=3x^2-88x+484

We move all terms to the left:

0-(3x^2-88x+484)=0

We add all the numbers together, and all the variables

-(3x^2-88x+484)=0

We get rid of parentheses

-3x^2+88x-484=0

a = -3; b = 88; c = -484;
Δ = b2-4ac
Δ = 882-4·(-3)·(-484)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-44}{2*-3}=\frac{-132}{-6}
=+22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+44}{2*-3}=\frac{-44}{-6}
=7+1/3
$